5-2(3x^2-2x)=7-2x^2

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Solution for 5-2(3x^2-2x)=7-2x^2 equation: 



5-2(3x^2-2x)=7-2x^2

We move all terms to the left:

5-2(3x^2-2x)-(7-2x^2)=0

We multiply parentheses

-(7-2x^2)-6x^2+4x+5=0

We get rid of parentheses

2x^2-6x^2+4x-7+5=0

We add all the numbers together, and all the variables

-4x^2+4x-2=0

a = -4; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·(-4)·(-2)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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